3.8.47 \(\int \frac {x^2 (a+b x)}{(c x^2)^{3/2}} \, dx\)

Optimal. Leaf size=35 \[ \frac {a x \log (x)}{c \sqrt {c x^2}}+\frac {b x^2}{c \sqrt {c x^2}} \]

________________________________________________________________________________________

Rubi [A]  time = 0.01, antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {15, 43} \begin {gather*} \frac {a x \log (x)}{c \sqrt {c x^2}}+\frac {b x^2}{c \sqrt {c x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^2*(a + b*x))/(c*x^2)^(3/2),x]

[Out]

(b*x^2)/(c*Sqrt[c*x^2]) + (a*x*Log[x])/(c*Sqrt[c*x^2])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {x^2 (a+b x)}{\left (c x^2\right )^{3/2}} \, dx &=\frac {x \int \frac {a+b x}{x} \, dx}{c \sqrt {c x^2}}\\ &=\frac {x \int \left (b+\frac {a}{x}\right ) \, dx}{c \sqrt {c x^2}}\\ &=\frac {b x^2}{c \sqrt {c x^2}}+\frac {a x \log (x)}{c \sqrt {c x^2}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.00, size = 21, normalized size = 0.60 \begin {gather*} \frac {x^3 (a \log (x)+b x)}{\left (c x^2\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^2*(a + b*x))/(c*x^2)^(3/2),x]

[Out]

(x^3*(b*x + a*Log[x]))/(c*x^2)^(3/2)

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.02, size = 23, normalized size = 0.66 \begin {gather*} \frac {a x^3 \log (x)+b x^4}{\left (c x^2\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(x^2*(a + b*x))/(c*x^2)^(3/2),x]

[Out]

(b*x^4 + a*x^3*Log[x])/(c*x^2)^(3/2)

________________________________________________________________________________________

fricas [A]  time = 1.11, size = 22, normalized size = 0.63 \begin {gather*} \frac {\sqrt {c x^{2}} {\left (b x + a \log \relax (x)\right )}}{c^{2} x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)/(c*x^2)^(3/2),x, algorithm="fricas")

[Out]

sqrt(c*x^2)*(b*x + a*log(x))/(c^2*x)

________________________________________________________________________________________

giac [A]  time = 0.99, size = 40, normalized size = 1.14 \begin {gather*} -\frac {\frac {a \log \left ({\left | -\sqrt {c} x + \sqrt {c x^{2}} \right |}\right )}{\sqrt {c}} - \frac {\sqrt {c x^{2}} b}{c}}{c} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)/(c*x^2)^(3/2),x, algorithm="giac")

[Out]

-(a*log(abs(-sqrt(c)*x + sqrt(c*x^2)))/sqrt(c) - sqrt(c*x^2)*b/c)/c

________________________________________________________________________________________

maple [A]  time = 0.00, size = 20, normalized size = 0.57 \begin {gather*} \frac {\left (a \ln \relax (x )+b x \right ) x^{3}}{\left (c \,x^{2}\right )^{\frac {3}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*(b*x+a)/(c*x^2)^(3/2),x)

[Out]

1/(c*x^2)^(3/2)*x^3*(a*ln(x)+b*x)

________________________________________________________________________________________

maxima [A]  time = 1.35, size = 23, normalized size = 0.66 \begin {gather*} \frac {b x^{2}}{\sqrt {c x^{2}} c} + \frac {a \log \relax (x)}{c^{\frac {3}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*(b*x+a)/(c*x^2)^(3/2),x, algorithm="maxima")

[Out]

b*x^2/(sqrt(c*x^2)*c) + a*log(x)/c^(3/2)

________________________________________________________________________________________

mupad [B]  time = 0.32, size = 30, normalized size = 0.86 \begin {gather*} \frac {b\,\relax |x|}{c^{3/2}}+\frac {a\,\ln \left (x+\relax |x|\right )}{c^{3/2}}-\frac {a\,x}{c^{3/2}\,\sqrt {x^2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^2*(a + b*x))/(c*x^2)^(3/2),x)

[Out]

(b*abs(x))/c^(3/2) + (a*log(x + abs(x)))/c^(3/2) - (a*x)/(c^(3/2)*(x^2)^(1/2))

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2} \left (a + b x\right )}{\left (c x^{2}\right )^{\frac {3}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*(b*x+a)/(c*x**2)**(3/2),x)

[Out]

Integral(x**2*(a + b*x)/(c*x**2)**(3/2), x)

________________________________________________________________________________________